import re
s = 'abc1234dklma567485dab1h四分司5發(fā)的6445595848555,12345 4444444444222222222222222Ifgood'
# 給數(shù)字添加分割號(hào)
p = re.sub(r'(?<=\d)(?=(?:\d{3})+(?!\d))',',',s)
# 給數(shù)字添加括號(hào)
k = re.sub(r'(?<=\d)(?!\d)',')',re.sub(r'(?<!\d)(?=\d)','(',s))
print(p)
print(k)
#打印結(jié)果
abc1,234dklma567,485dab1h四分司5發(fā)的6,445,595,848,555,12,345 4,444,444,444,222,222,222,222,222Ifgood
abc(1234)dklma(567485)dab(1)h四分司(5)發(fā)的(6445595848555),(12345) (4444444444222222222222222)Ifgood
關(guān)于正則表達(dá)式有其他需求的,可在評(píng)論區(qū)留言